Basic Physics question: If you push an object 4 m horizontally on the table and then pushed it vertically for a distance of 3 m. What will be the Work done on the object?
I know that W=|F||d|cos Ø I'm not sure if i will use the total Distance or the displcement to calculate for work. |dw:1397078762428:dw|
*displacement
if i'll use total distance, it will be 7 m if i'll use the displacement it will be 5 m which one is the right thing?
Work is being done both pushing the object horizontally 4 m, and then lifting it vertically a distance of 3 m. Each of these two things requires energy input.
so it means I should consider the the total distance which is 7 m?
Me thinks you should break it up into two parts. The amount of force needed for horizontal motion doesn't necessarily mean you'l use the same force in vertical motion.
It might in this problem if the table is frictionless...
hmm..let's assume friction is negligible and the force applied is 3 N for both motions, if i break it into two parts, i still need to calculate for the total work done, which will give me 21 J (same amount of work if i use the total distance by the object)
|dw:1397081201611:dw|
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