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Physics 14 Online
OpenStudy (anonymous):

Basic Physics question: If you push an object 4 m horizontally on the table and then pushed it vertically for a distance of 3 m. What will be the Work done on the object?

OpenStudy (anonymous):

I know that W=|F||d|cos Ø I'm not sure if i will use the total Distance or the displcement to calculate for work. |dw:1397078762428:dw|

OpenStudy (anonymous):

*displacement

OpenStudy (anonymous):

if i'll use total distance, it will be 7 m if i'll use the displacement it will be 5 m which one is the right thing?

OpenStudy (anonymous):

Work is being done both pushing the object horizontally 4 m, and then lifting it vertically a distance of 3 m. Each of these two things requires energy input.

OpenStudy (anonymous):

so it means I should consider the the total distance which is 7 m?

OpenStudy (ipwnbunnies):

Me thinks you should break it up into two parts. The amount of force needed for horizontal motion doesn't necessarily mean you'l use the same force in vertical motion.

OpenStudy (ipwnbunnies):

It might in this problem if the table is frictionless...

OpenStudy (anonymous):

hmm..let's assume friction is negligible and the force applied is 3 N for both motions, if i break it into two parts, i still need to calculate for the total work done, which will give me 21 J (same amount of work if i use the total distance by the object)

OpenStudy (anonymous):

|dw:1397081201611:dw|

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