State the amplitude, period, phase shift, and verticle translation for y = -sin(x-pi/4)+2
\[y = -\sin(x-\frac{ \pi }{ 4 })+2\]
@TeresaCal Last trig function problem, thanks a ton for the help on the last one :)
The general formulas for sine and cosine are y = Asin(Bx C) + D and y = Acos(Bx C) + D. We shall begin by labeling the various components. A amplitude of the function = (max-min)/2 (vertical stretch of the graph) B stretch/shrink on the x-axis. (It compresses or expands the graph.) C/B the phase shift of the graph (the shift left (if C/B is neg.) or right (if C/B is pos.)) D the vertical shift of the graph.
Starting with amplitude, A = 1 correct?
Anything before "sin" is included with A. So A = -1
Alright, now B. B = 1 right?
I would assume 1 just takes the place considering there is nothing there. Sorry, I'm not used to seeing functions set up like this.
Yes, B = 1 in this case
Okay, and I know to find the period it is 2pi/B so in this case, the period is simply 2pi correct?
Correct again
Excellent, now for the phase shift. Would the answer for phase shift be written simply as "pi/4 units to the right"?
Sounds about right :)
Alrighty and vert shift is 2 units up of course
Hang on...
Oh wait, phase shift would be horizontal compression right?
No, don't get those two things confused.
Phase Shift is C/B In this case, B = 1 so C/B = pi/4
If B was anything other than 1, then the phase shift would be different from the horizontal compression
Only when B = 1 does phase shift = horizontal compression
Okay okay :) One of the trickiest parts for me is keeping the whole horizontal/verticle compression and stuff.
Well that just about does it @Hero Thank you so much for all the help and I wish I could give more medals!
One medal is good enough, thanks :)
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