Assuming that voltage remains constant, what happens to the current in a filament if it is replaced by a thinner wire? A. The current increases. B. The current decreases. C. The current is not affected by a change in filament thickness. D. The current alternates between high and low values
The resistance of a wire is given by:\[R=\frac{ \rho L }{ A}\]where R is the resistance; ρ is the resistivity (an intrinsic property of the wire material); L is the length of the wire; and A is the cross-sectional area of the wire. Alas, you need to to know happens to current. So let's write Ohm's law as follows:\[I=\frac{ V }{ R }\]And now let's insert the first equation into our second:\[I=\frac{ VA }{ \rho L }\]Voltage is constant; L is constant; and ρ is constant. The only things varying are the current, I, and the cross sectional area, A. Now, a thinner wire has a smaller A, so to answer your question, in our last equation, what happens to I as A gets small?
Join our real-time social learning platform and learn together with your friends!