if 40.27 ml of .1 M NaOH is required to neutralize .314 g of an unknown monoprotic acid, what is the molecular weight of this unknown acid

Question

joannablackwelder · Answer

So, to find the molecular weight of the acid we need to find the moles of the acid that are neutralized.

joannablackwelder · Answer

I did that by writing the reaction
HX + NaOH -> H2O + NaX 
since it is monoprotic, it just has 1 H.

joannablackwelder · Answer

Then I found the moles of NaOH using moles = V*c (watch your units) and moles of HX by the reaction mole ratio.

joannablackwelder · Answer

Molecular weight would be grams reacted (given)/mol reacted.

joannablackwelder · Answer

Welcome to OpenStudy! Let me know if you have any questions.

anonymous · Answer

Thanks!!

joannablackwelder · Answer

Glad to help. :)