Question

I need to know if I am did this right. please help me

Answer 1

ok \[\sqrt{7r+2}+3=7 \] dose it have no solution

Answer 2

yes, it has

Answer 3

it has one ?

Answer 4

may be, let see. -3 both sides.
square both sides
simplify
done

Answer 5

ok but dose it have a solution?

Answer 6

yes

Answer 7

I need to know if I am did this right <---- what did you get that may not be right?

Answer 8

ok so what did you do

Answer 9

again, YES, it has

Answer 10

\[\sqrt{7r + 2} +3=7\rightarrow \sqrt{7r+2}=4 \]
\[7r+2=4^{2} \rightarrow 7r+2=16\]
\[7r=14\rightarrow r=7\]

Answer 11

ineedhelpnow08 \(\huge \checkmark\)

Answer 12

well... wait... shoot.... spoke too soon

anyhow

Answer 13

\(\bf \sqrt{7r+2}+3=7\implies \sqrt{7r+2}=4\implies 7r+2=4^2
\\ \quad \\
7r=16-2\implies r=\cfrac{14}{7}\)

Answer 14

oh yeah my bad14/7 is 2

Answer 15

yeap

Answer 16

thx