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Find the value of c such that the point (2, 5) lies on the graph of f(x) = cx^2 + 4x − 2. c=
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All points are of the form (x,y) So, (x,y) = (2, 5) which means x = 2, y = 5
So the idea is that if you plug in x = 2, you should get y = 5 or f(x) = 5
f(x) = cx^2 + 4x − 2 f(x) = c(2)^2 + 4(2) − 2 ... plug in x = 2 5 = c(2)^2 + 4(2) − 2 ... plug in f(x) = 5 now solve for c
so c=2?
c = 2 is incorrect
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would the answer be -5?
5 = c(2)^2 + 4(2) − 2 5 = c(4) + 4(2) − 2 5 = 4c + 8 - 2 5 = 4c + 6 c = ??
-1/4?
better
Thanks! people are very helpful
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