Question

someone please help!!!!!!!!!!!!!

Answer 1

if need help type of upload a picture of the problem

Answer 2

yeah sorry i was about to upload a pic

Answer 3

i dont know if you could see that or not???

Answer 4

and last one, i promise haha

Answer 5

\[x ^{3}+3x ^{2}-18x \rightarrow x(x^{2}-3x-18)\]
thus
\[x(x^{2}-3x-18)=(x)(x+6)(x-3)\]

Answer 6

that is question 24

Answer 7

wait im so confused?

Answer 8

@ineedhelpnow08

Answer 9

confused on what part?

Answer 10

thats not the final answer right, so what else do i do after that?

Answer 11

it is its the 3rd choice

Answer 12

x , (x+6) and (x-3)

Answer 13

ohhhhh okay thank you!!

Answer 14

do you know how to do the rest?

Answer 15

wait thats the second choice lol

Answer 16

wait wait its
b)x,x+3 and x-6
c)x,x-3 and x+6

Answer 17

its the 3rd one, (x+6)

Answer 18

and nooo i actually dont these problems were the hardest on the it was 25 questions and i didnt understand these

Answer 19

alright first you simplified it, on question 24's case you take the x out side to get x(x2−3x−18)

Answer 20

isnt the problem x^3+3x^2-18x

Answer 21

how'd you get that????

Answer 22

yes, you can simplify it finding the greatest common factor which is x
so you can bring it out and get x(x^2+3x-18)

Answer 23

it basically means x times the expression in the parenthesis which you can get the original answer

Answer 24

ohhh right the gcf, if you're not busy can you walk me through the rest?

Answer 25

ill go over this problem then i got to go to sleep big AP calc test tomarrow

Answer 26

when you get x(x^2−3x−18)
you factor it out
(x)(x+6)(x−3) and should get these

Answer 27

omg no thats okay you should go, sorry!

Answer 28

its alright

Answer 29

him maybe i could find others to help

Answer 30

@jim_thompson5910 sorry, can you help out a bit i got to go

Answer 31

hahaha thanks

Answer 32

no problem, he might be busy though so yeah..

Answer 33

its okay i can wait, but you should go sleep lol calculus is hard, so ive heard

Answer 34

yeah, not doing so hot in that class, well good night!

Answer 35

aw, haha night!

Answer 36

To factor x^2+3x-18, you need to find two numbers that


multiply to -18 (last term)
AND
add to 3 (middle term)

Answer 37

so what two numbers multiply to -18 AND add to 3?

Answer 38

6 x 3 and 9 x 2 ?

Answer 39

oh wait you said negative

Answer 40

yeah we need -18, not +18

Answer 41

-6 x 3

Answer 42

-9 x 2

Answer 43

am i right?

Answer 44

-6 x 3 = -18 ... works

-6 + 3 = -3 ... doesn't work (we need +3, not -3)

Answer 45

so are you trying say it would be x, x +3 and x-6?

Answer 46

no I'm saying that the two numbers aren't -6 and 3 because -6 + 3 = -3

we want the two numbers to add to positive 3 (the coefficient of the middle term)

Answer 47

however, the two numbers 6 and -3 work since

6 * (-3) = -18
6 + (-3) = 3

Answer 48

which means x^2 + 3x - 18 factors to (x+6)(x - 3)

Answer 49

wait does order matter because thats not one of the choices

Answer 50

order doesn't matter

Answer 51

(x+6)(x-3) is the same as (x-3)(x+6)

since you can multiply in any order

Answer 52

oh okay thanks!

Answer 53

you're welcome

Answer 54

okay how about this one

Answer 55

what is the factored form of the expression?
t^2 - 25

Answer 56

hint: 25 is a perfect square (since 5^2 = 25)

Answer 57

im confused would it be (t+25)(t-1) or (t+5)^2

Answer 58

you would use the difference of squares formula

\[\Large a^2 - b^2 = (a+b)(a-b)\]

Answer 59

in this case, a = t, b = 5, so...


\[\Large a^2 - b^2 = (a+b)(a-b)\]


\[\Large t^2 - 5^2 = (t+5)(t-5)\]


\[\Large t^2 - 25 = (t+5)(t-5)\]

Answer 60

ohhhh factoring right sorry i was doing something else but thank you! for helping out lol

Answer 61

you're welcome

Answer 62

can you help me with about 4 more?

Answer 63

i mean only if you want! and you're not busy or anything

Answer 64

sure I can help

Answer 65

a freezer has a volume given by the trinomial y^3 -2y^2-35y. what are the possible dimensions of the box. use factoring.

Answer 66

first factor out the GCF

Answer 67

the gcf of?

Answer 68

of the 3 terms

Answer 69

what is the greatest common factor of y^3, -2y^2, -35y

Answer 70

how would you get a gcf out of them all? i dont get it i mean i can get a gcf out of one, should i do them each separately

Answer 71

think of y^3 as y*y*y

Answer 72

think of y^2 as y*y

Answer 73

so we really have these 3 terms

y*y*y
-2*y*y
-35*y

what is the common factor in ALL 3 terms?

Answer 74

there isnt a number that both goes through -2 and -35 so i dont get it?

Answer 75

the common factor would be y though ? idk i feel so stupid

Answer 76

you are correct, it is y

Answer 77

y is found in all 3 terms, so that's the GCF

Answer 78

what do you get when you factor out the GCF y?

Answer 79

you get 2 - 35

Answer 80

wait factor?

Answer 81

y^3 - 2y^2 - 35y


y*y*y - 2y*y - 35y ... break up y^3 and y^2


y( y*y - 2*y - 35 ) ... use the distributive property to factor out y


y( y^2 - 2y - 35) ... multiply y*y to get y^2

Answer 82

see how I'm getting that?

Answer 83

i thin kso

Answer 84

now you must factor y^2 - 2y - 35

Answer 85

......

Answer 86

to factor y^2 - 2y - 35, you must find two numbers that multiply to -35 and add to -2

Answer 87

,-5 x 7 equals -35

Answer 88

but -5 + 7 = +2

Answer 89

so am i supposed to multiply or add?

Answer 90

-5 times 7 = -35, that is correct

but -5 + 7 is NOT -2 like we want

Answer 91

if we swap the signs, we get

5 times -7 = -35

5 + (-7) = -2

so both now work