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Mathematics 13 Online
OpenStudy (anonymous):

how does this simplify to one?!

OpenStudy (anonymous):

OpenStudy (anonymous):

want some beer?

OpenStudy (anonymous):

Wow, Sourwing, WTH?

OpenStudy (anonymous):

nick, would you like some beer too? there's plenty :DD

OpenStudy (anonymous):

Well, what brew?

OpenStudy (anonymous):

Ela, coming up with an answer for you.

OpenStudy (anonymous):

BudLight :DD

OpenStudy (anonymous):

dude, if youre gonna try to intoxicate unsuspecting victims at least do it with like candy or something

OpenStudy (anonymous):

I'm a Blue Moon man, myself. Thanks though, Sourwing. 'Precciate it.

OpenStudy (anonymous):

ok :3

OpenStudy (anonymous):

Okay, so while x=-3, then this is what's happening: The condition described here; ( (-1)^n * (-2)^n) ) / (2)^n ...Is equal to one when x=-3. You can see that when you fill in n with -3. Does this help you?

OpenStudy (anonymous):

well actually -3 was substituted for x not in in this summation @NickDantzlerward

OpenStudy (anonymous):

I'm sorry, I must not understand, what happened?

OpenStudy (anonymous):

this was the original summation

OpenStudy (anonymous):

basically this is the whole problem...

OpenStudy (anonymous):

OpenStudy (anonymous):

So x=-3 still, correct?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

I'm just wondering how that specific part simplified to 1 ?

OpenStudy (anonymous):

That there...is a sexy-looking problem. I'm not actually deeply familiar with this 'interval of convergence' concept, but I'm gonna study the brains out of it tonight. I think I understand it a little bit...I will solve this. I absolutely will. I'll get back to you as quickly as I can.

OpenStudy (anonymous):

@NickDantzlerward oh thank you! i appreciate it!

OpenStudy (anonymous):

Ha-ha...Absolutely. Y'know how it is though, as soon as I learn something amazing, someone's already given you a solution. XD I'll see what I can do.

OpenStudy (anonymous):

Yikes, hey Ela, I know this seems crazy, but I really want to know how these work. Do you think that actually you might be able to show me the basics of how these are done? Looks like I need help now... :D As soon as I get how these work, then I can find the reasoning behind all the problems like the one you showed me.

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