Question

Any ideas will help, or discussion: Identify the sturcutres A & B

Answer 1

\(\sf [(\eta^6-C_6H_6)Mn(CO)_3]^+ + PBu_3 \rightarrow \color{red}{A} \rightarrow \color{blue}{B}\)
Product A is subject to UV light to form product B.

Answer 2

Given the Data:
IR (cm\(^-\)) for \(\sf \color{green}{ [(\eta^6-C_6H_6)Mn(CO)_3]^+} \)
2080, 2026
H-NMR (\(\delta\))
6.90

while product A IR (cm\(^-\))
2028, 1950
H-NMR (\(\delta\))
6.30 (1H)
5.50 (2H)
4.40 (1H)
3.40 (2H)
which includes resonance due to the PBu\(_3\)

and Product B: IR (cm\(^-\))
1997, 1950
H-NMR (\(\delta\))
6.42
includes resonance also

Answer 3

Well all I remember is that eta 6 notation means that the benzene ring is bonded with all 6 pi orbitals like a sandwich compound.

One thing to note is that after light is used there's not as much of a shift in the IR so you're probably losing something electronegative. At least I think that's how the trend goes, it's not a really big difference and I was never really all that interested in IR.

Answer 4

If the question is still here Friday/Saturday or so I'll get out my inorganic textbook and try to help figure it out with you since I sort of don't want to forget it.

Also, if you could name it or draw the structure that would be helpful to me since I'm not really sure what this looks like.

Answer 5

I think this is the structure. I don't remember much from inorganic.

Answer 6

@abb0t can you help me with my chem hw?