A triangle has side lengths of 34 in., 28 in., and 42 in. Is the triangle acute, obtuse, or right?
My guess is obtuse, but I'm not sure.
If \(\rm (longest~side)^2 = (one ~leg)^2 + (other~leg)^2\), then right. If \(\rm (longest~side)^2 > (one ~leg)^2 + (other~leg)^2\), then obtuse. If \(\rm (longest~side)^2 < (one ~leg)^2 + (other~leg)^2\), then acute.
Compare a^2 + b^2 to c^2 If they're equal, it's right (Pythagorean thm) If c^2 is greater than a^2 +b^2, it's obtuse If c^2 is less than a^2 +b^2, it's acute
OK, then I think I'm right. I'll do the math first though.
\[28\times28=784\]\[34\times34=1156\]\[784+1156=1940\]\[\sqrt{1940}=44\]So it is obtuse.
Thank you @ParthKohli and @bernadettegu
\[42^2 = 1764\]and\[28^2 + 34^2 = 1940 \]Which one is greater?
The second one.
So look at the conditions I gave.
So because it's longer then the longest side squared, it's obtuse.
The conditions are simple... see again.
\[42^2 < 28^2 + 34^2\]that's all.
Ok I see. Thanks for actually teaching me.
Hmm, the answer you get is still not right.
If \(\rm (longest~side)^2 < (one ~leg)^2 + (other~leg)^2\), the acute.
Oh, I kept reading it backwards.
Ah, all right...
So it's acute not obtuse.
Right.
The correct answer is . Acute
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