Find the solutions to the systems
9. y=x^2+5x+6
y=4x+12
A. (2,20) and (-3,0)
B. (2,20) and (-3,-18)
C. (-2,-20) and (-3,-18)
D. no solutions

10. y=x^2-3x-1
y=8x-1
A. (0,-1) and (11,388)
B. (0,-1) and (11,87)
C. (-1,0) and (87,11)
D. no solutions

Question

Find the solutions to the systems
9. y=x^2+5x+6
    y=4x+12
A. (2,20) and (-3,0)
B. (2,20) and (-3,-18)
C. (-2,-20) and (-3,-18)
D. no solutions

10. y=x^2-3x-1
      y=8x-1
A. (0,-1) and (11,388)
B. (0,-1) and (11,87)
C. (-1,0) and (87,11)
D. no solutions

anonymous · Answer

@ganeshie8 
@ParthKohli 
help please(:

parthkohli · Answer

$$y =x^2 + 5x+6$$$$y = 4x + 12$$Basically, since $y$ is equal to both of these things, we have$$x^2 + 5x + 6 = 4x + 12$$Arrange all the terms on one side and you'll have a quadratic equation with you.

ankitshaw · Answer

|dw:1397136326104:dw|

johnweldon1993 · Answer

y=x^2+5x+6
y=4x+12

Set them equal to each other

x^2 + 5x + 6 = 4x + 12

combine like terms

x^2 + x - 6 = 0

Factor out

(x + 3)(x - 2) = 0

x would be -3 and 2

parthkohli · Answer

You'll have to similarly work with the other question.

johnweldon1993 · Answer

Then of course...you would plug those 2 x-values you have received into your equations again to find out what the y-coordinate will be

johnweldon1993 · Answer

Similarly with number 10

y=x^2-3x-1
y=8x-1

Set them equal to each other

x^2 - 3x - 1 = 8x - 1

And continue on from there combining like terms and factoring :)

anonymous · Answer

thanks everyone <3 @xxraider365  @johnweldon1993 @ParthKohli

anonymous · Answer

oh and @ankitshaw :)