Question

10+9+8+7+6+5+4+3+2+1

Answer 1

55 is answer

Answer 2

n(n+1)/2 will give u the answer where n is the last number

Answer 3

u can use my eqn for sum of any no of natural nos

Answer 4

\[\sum_{i=1}^{n}i = n + (n-1) + (n-2) + ... + 3+2+1 = \dfrac{n(n+1)}{2}\]

Answer 5

Like what @ankitshaw said.

Answer 6

@geerky42 thnax for that derivation its very imp to understand how a formula is derived

Answer 7

np @ankitshaw

Is that clear? @ikatouni

Answer 8

thanks guys