Question

Please help with this one question??

1. A container holds 15 pennies, 8 nickels, and 10 dimes. You will randomly select two coins without replacement. Show your work!
a. How many ways can you select the coins?
b. How many ways can you select exactly 1 nickel?
c. What is the probability that you select 2 pennies?
d. What is the probability that you select a dime and then a penny?
Then, you should get...

A. Fill in the probabilities on each branch of the tree diagram. (I don't get this part)
https://www.flickr.com/photos/102326650@N03/13744724835/

(Is this the right answe

Answer 1

(Is this the right answer for a-d?)

(15 + 8 + 10)! = 33! ways

1b. How many ways can you select exactly 1 nickel?

Then, that would be 1 * (15 + 10)! = 25! ways

1c. What is the probability that you select 2 pennies?

That is easy if you are only allowed to select up to 2 coins...

P(2 pennies) = 15/33 * 14/32

1d.

P(a dime and a penny) = 10/33 * 15/32

Answer 2

Or is this the right answer?
a. 33C2 = 528 (not 33!)

b. How many ways to select 1 nickel:
(8C1)(25C1) = 8(25) = 200

c. Probability of selecting 2 pennies:
(15C2)/(33C2) = 35/176 = .19886

d. Probability of dime then penny:
10/33 * 15/32 = 25/176 = .142