Solve y´=0 if y=2sin(x)+4cos(x)

I got it to:
y=2sin(x)+4cos(x)
y´= 2cos(x)-4sin(x)

divide by 2 for simplicity, get cos(x)-2sin(x) = 0

Now where do I go from here?

Question

Solve y´=0 if y=2sin(x)+4cos(x) 

I got it to: 
y=2sin(x)+4cos(x) 
y´= 2cos(x)-4sin(x)

divide by 2 for simplicity, get cos(x)-2sin(x) = 0

Now where do I go from here?

luigi0210 · Answer

Hmm, I'd assume to find the solutions where $cos(x)=2sin(x)$?

luigi0210 · Answer

Hmm.. how about we divide by cos? $\large \frac{2sinx}{cosx}=1$. That'll leave us with $\large 2tanx=1$ and finally $tanx=\frac{1}{2}$. Is that easier?

anonymous · Answer

IT WORKEEEED!!! YAAAAYYY!! AWESOME!!! THANK YOU, I GOT IT TO 26.56 DEGREES!

anonymous · Answer

@Luigi0210  THANK YOU!

luigi0210 · Answer

I honestly had no idea either.. I just tried what I could, glad it work, and you're welcome :)