Derivative of x^3*e^(2x)
I get different results when I check my answer to Wolfram Alpha and derivativecalculator.net

Please help, it should be easy.

Question

Derivative of x^3*e^(2x)
I get different results when I check my answer to Wolfram Alpha and derivativecalculator.net

Please help, it should be easy.

ganeshie8 · Answer

use chain rule

ganeshie8 · Answer

and product rule

ganeshie8 · Answer

$\large        \mathbb    [x^3*e^{2x} ]'   =    x^3 [e^{2x}]'  +   [x^3]' e^{2x}$

anonymous · Answer

What? 

f´(x) = $$\frac{ d }{ dx }\left( x^3 \right) * e^(2x) + x^3* \frac{ d }{ dx }\left( e ^{2x}\right)$$

ganeshie8 · Answer

looks good^

anonymous · Answer

$$suppose~ y=x^3e^(2x) $$
$$if  ~y=uv,y'=uv'+u'v$$

anonymous · Answer

Then I get: 

$$3x^2 * e ^{2x} + x^3* 2e ^{2x}$$ which seems to be wrong...or?

ganeshie8 · Answer

It is correct !

ganeshie8 · Answer

did wolfram give a different answer ?

anonymous · Answer

but not according to wolfram alpha...though. Maybe I did it wrong...

anonymous · Answer

yes

ganeshie8 · Answer

http://www.wolframalpha.com/input/?i=%28x%5E3*e%5E%282x%29%29%27

ganeshie8 · Answer

wolfram just factored the answer

anonymous · Answer

ot may be$$x^2e ^{2x}\left( 2x+3 \right)$$

ganeshie8 · Answer

factor out the GCF in your answer

anonymous · Answer

Aaaah, now I get it...if was factored ,yes @ganeshie8. Thank you all. I don't seem to know what I'm doing haha.

ganeshie8 · Answer

:) you're doing it correctly.... and yes its always good to double/triple confirm wid wolfram !