Question

a ski lift begins at ground level 0.75 mile from the base of a mountain whose face has a 50 angle of elevation, as shown in the accompanying diagram. the ski lift ascends in a straight line at an angle of 20. find the length of the ski lift from the beginning of the ski lift to the top of the mountain, to the nearest hundredth of a mile.

Answer 1

anyone plz help! thnks:)

Answer 2

\[\frac{3}{4} \sin (50 {}^{\circ}) \csc (20 {}^{\circ})=1.68 \]

Answer 3

@robtobey

Answer 4

can u plz explain how u got 1.68?

Answer 5

and wht formula r u using?

Answer 6

@myininaya

Answer 7

@Loser66 @mathmale

Answer 8

Hello, lyubas!

Let's start with your question. How do we get 1.68 from\[\frac{3}{4} \sin (50 {}^{\circ}) \csc (20 {}^{\circ})=1.68?\]
Please set your calculator to DEGREE mode if you can.

Now type in (3/4)sin (50). What do you get?

Answer 9

he;;o :) I got .5745333323

Answer 10

Next, lyubas, remember that csc 20 is exactly the same as 1 divided by sin 20.
So, take the result of your calculation and divide it by sin (20). What do you get this time?

Answer 11

1.68

Answer 12

@mathmale

Answer 13

So, lyubas, you have answered your own question! :)

Answer 14

but formula did we use?

Answer 15

Good point. I hadn't asked myself that question. Just a moment, please. In the meantime, why not get started on your next question?

Answer 16

alrighty:) il type it now

Answer 17

in triangle ABC, a=3 b=5 c=7. what is the angleC?

Answer 18

so I kinda started it but I couldn't finish it cani tel u what I did so far