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Mathematics 19 Online
OpenStudy (anonymous):

Find a formula for 1) the area of the figure **is it xy+(πr^2/2) ? **** 2) the perimeter of the figure ****is it x + x + y + (π * y / 2 ) ? **** And then find the dimensions of x and y that maximize the area given that the perimeter is 500. write EXACT answers x=____ ; y= _______ thanks!! @ganeshie8 ?

OpenStudy (anonymous):

FIGURE! :)

ganeshie8 (ganeshie8):

so you have a rectangle and a semicircle

ganeshie8 (ganeshie8):

whats the radius of semicircle ?

OpenStudy (anonymous):

1/2 diameter?

ganeshie8 (ganeshie8):

yes, so r = y/2 right ?

ganeshie8 (ganeshie8):

that gives area of semicircle = \(\huge \frac{\pi (\frac{y}{2})^2}{2}\)

OpenStudy (anonymous):

yes:)

OpenStudy (anonymous):

so area of this figure is xy + (pi(y/2)^2 / 2)) ?

ganeshie8 (ganeshie8):

yup ! simplifying it gives : Area of entire figure = \(\huge xy + \frac{\pi }{8}y^2\)

OpenStudy (anonymous):

ahh ok:)

OpenStudy (anonymous):

Area of the rectangle:\[A=lw=xy\] Area of 1/2 circle \[A=\frac{\pi r^{2}}{2}=\frac{\pi (y/2)^{2}}{2}\] Total area \[A=A_{rect}+A_{1/2circ}=xy+\frac{\pi (y/2)^{2}}{2}\] From there you can simplify if need be to \[xy+\frac{\pi}{8}y^{2}\]

OpenStudy (anonymous):

ahh so what about the perimeter?

ganeshie8 (ganeshie8):

perimeter looks good !

OpenStudy (anonymous):

yay!! so what about the last part then?

ganeshie8 (ganeshie8):

And then find the dimensions of x and y that maximize the area given that the perimeter is 500.

OpenStudy (anonymous):

how do we do that?

ganeshie8 (ganeshie8):

set the perimeter equal to 500 and solve x or y

ganeshie8 (ganeshie8):

x + x + y + (π * y / 2 ) = 500

ganeshie8 (ganeshie8):

looks, solving x is easy, so lets sovle x

OpenStudy (anonymous):

so 2x + y + (pi * y / 2) = 500

ganeshie8 (ganeshie8):

yes, solve x all the way, then plug that value in Area expression

OpenStudy (anonymous):

so 2x + πy/2 = 500 -y ?

ganeshie8 (ganeshie8):

so 2x + y + (pi * y / 2) = 500 2x = 500 - y - (pi * y / 2) x = 250 - y/2 - (pi * y / 4)

ganeshie8 (ganeshie8):

^^

ganeshie8 (ganeshie8):

plug this x value in earlier Area formula

OpenStudy (anonymous):

okay following :)

OpenStudy (anonymous):

so \[A=250-\frac{ y }{ 2 } - (\frac{ πy }{ 4 })y + (\frac{ πr^2 }{ 2 })\] like this?

ganeshie8 (ganeshie8):

\(\huge A = xy + \frac{\pi }{8}y^2 \)

ganeshie8 (ganeshie8):

plugin \(x = 250 - y/2 - (\pi * y / 4) \)

OpenStudy (anonymous):

so 250 y - (y^2/2) - (pi*y/4) ?

ganeshie8 (ganeshie8):

\(\large A = [250 - \frac{y}{2}- \frac{\pi y }{4} ]y + \frac{\pi }{8}y^2 \)

ganeshie8 (ganeshie8):

simplify it if u want, and maximize

OpenStudy (anonymous):

okay.. so \[A=250y - \frac{ y^2 }{ 2 } - \frac{ πy^2 }{ 4 } + \frac{ πy }{ 4 }\] ?

ganeshie8 (ganeshie8):

hmm check ur last term again

OpenStudy (anonymous):

ermm not sure how to simplify that part :/

ganeshie8 (ganeshie8):

\(\large A = [250 - \frac{y}{2}- \frac{\pi y }{4} ]y + \frac{\pi }{8}y^2 \) distribute y : \(\large A = 250y - \frac{y^2}{2}- \frac{\pi y^2 }{4} + \frac{\pi }{8}y^2 \) pull out y^2 : \(\large A = 250y - y^2[\frac{1}{2} + \frac{\pi }{4} - \frac{\pi }{8}] \) simplify : \(\large A = 250y - y^2[\frac{4+\pi }{8}] \)

ganeshie8 (ganeshie8):

Maximize it !

OpenStudy (anonymous):

set it equal to 0?

ganeshie8 (ganeshie8):

find the derivative first

ganeshie8 (ganeshie8):

then u can set it equal to 0 and solve y

OpenStudy (anonymous):

250 + .... not sure how to derive that second part :/

ganeshie8 (ganeshie8):

let me ask u a q : whats the derivative of y^2*10 ?

OpenStudy (anonymous):

wait would it be A' = 250 + 1/4(4+π)y ? :/

OpenStudy (anonymous):

y^(2*10) ?

ganeshie8 (ganeshie8):

Perfect ! set it equal to 0 and sovle y

OpenStudy (anonymous):

oh just 2y+0 ?

ganeshie8 (ganeshie8):

forget about my q, u got the derivative correct ! set it equal to 0 and sovle y :)

OpenStudy (anonymous):

250 + 1/4(4+π)y = 0 so 250 +y+πy = 0 ?

ganeshie8 (ganeshie8):

wait a sec, u have flipped hte sign

ganeshie8 (ganeshie8):

\(\large A = 250y - y^2[\frac{4+\pi }{8}]\) \(\large A' = 250 - 2y[\frac{4+\pi }{8}]\)

ganeshie8 (ganeshie8):

set it equal to 0 and sovle y

ganeshie8 (ganeshie8):

\(\large 250 - 2y[\frac{4+\pi }{8}] = 0 \) \(\large y[\frac{4+\pi }{4}] = 250 \) \(\large y[4+\pi ] = 1000 \) \(\large y = \frac{1000}{4 + \pi} \)

ganeshie8 (ganeshie8):

So, the max value occurs at \(\large y = \frac{1000}{4 + \pi} \)

OpenStudy (anonymous):

ahh okay so that's it? x= 250 y - (y^2/2) - (pi*y/4) and y = what you just typed?

OpenStudy (anonymous):

@ganeshie8 did i get that x value right? :/

ganeshie8 (ganeshie8):

u need to sovle x

ganeshie8 (ganeshie8):

u have : x + x + y + (π * y / 2 ) = 500

ganeshie8 (ganeshie8):

plugin y value in this, and solve x

ganeshie8 (ganeshie8):

you should get : \(\large x = \frac{500}{4 + \pi}\)

OpenStudy (anonymous):

2x + (1000/4+π) + (π*(1000/4+π / 2) = 500 ?

ganeshie8 (ganeshie8):

simplify it in any way u wish ! test for ur algebra skills :P

OpenStudy (anonymous):

ahh okay:P thank you!!!

OpenStudy (anonymous):

i got 500/4+pi on my paper :) it got messy!! hahahaa

OpenStudy (anonymous):

hehe thanks!! :D

ganeshie8 (ganeshie8):

np :)

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