Find a formula for 1) the area of the figure **is it xy+(πr^2/2) ? **** 2) the perimeter of the figure ****is it x + x + y + (π * y / 2 ) ? **** And then find the dimensions of x and y that maximize the area given that the perimeter is 500. write EXACT answers x=____ ; y= _______ thanks!! @ganeshie8 ?
FIGURE! :)
so you have a rectangle and a semicircle
whats the radius of semicircle ?
1/2 diameter?
yes, so r = y/2 right ?
that gives area of semicircle = \(\huge \frac{\pi (\frac{y}{2})^2}{2}\)
yes:)
so area of this figure is xy + (pi(y/2)^2 / 2)) ?
yup ! simplifying it gives : Area of entire figure = \(\huge xy + \frac{\pi }{8}y^2\)
ahh ok:)
Area of the rectangle:\[A=lw=xy\] Area of 1/2 circle \[A=\frac{\pi r^{2}}{2}=\frac{\pi (y/2)^{2}}{2}\] Total area \[A=A_{rect}+A_{1/2circ}=xy+\frac{\pi (y/2)^{2}}{2}\] From there you can simplify if need be to \[xy+\frac{\pi}{8}y^{2}\]
ahh so what about the perimeter?
perimeter looks good !
yay!! so what about the last part then?
And then find the dimensions of x and y that maximize the area given that the perimeter is 500.
how do we do that?
set the perimeter equal to 500 and solve x or y
x + x + y + (π * y / 2 ) = 500
looks, solving x is easy, so lets sovle x
so 2x + y + (pi * y / 2) = 500
yes, solve x all the way, then plug that value in Area expression
so 2x + πy/2 = 500 -y ?
so 2x + y + (pi * y / 2) = 500 2x = 500 - y - (pi * y / 2) x = 250 - y/2 - (pi * y / 4)
^^
plug this x value in earlier Area formula
okay following :)
so \[A=250-\frac{ y }{ 2 } - (\frac{ πy }{ 4 })y + (\frac{ πr^2 }{ 2 })\] like this?
\(\huge A = xy + \frac{\pi }{8}y^2 \)
plugin \(x = 250 - y/2 - (\pi * y / 4) \)
so 250 y - (y^2/2) - (pi*y/4) ?
\(\large A = [250 - \frac{y}{2}- \frac{\pi y }{4} ]y + \frac{\pi }{8}y^2 \)
simplify it if u want, and maximize
okay.. so \[A=250y - \frac{ y^2 }{ 2 } - \frac{ πy^2 }{ 4 } + \frac{ πy }{ 4 }\] ?
hmm check ur last term again
ermm not sure how to simplify that part :/
\(\large A = [250 - \frac{y}{2}- \frac{\pi y }{4} ]y + \frac{\pi }{8}y^2 \) distribute y : \(\large A = 250y - \frac{y^2}{2}- \frac{\pi y^2 }{4} + \frac{\pi }{8}y^2 \) pull out y^2 : \(\large A = 250y - y^2[\frac{1}{2} + \frac{\pi }{4} - \frac{\pi }{8}] \) simplify : \(\large A = 250y - y^2[\frac{4+\pi }{8}] \)
Maximize it !
set it equal to 0?
find the derivative first
then u can set it equal to 0 and solve y
250 + .... not sure how to derive that second part :/
let me ask u a q : whats the derivative of y^2*10 ?
wait would it be A' = 250 + 1/4(4+π)y ? :/
y^(2*10) ?
Perfect ! set it equal to 0 and sovle y
oh just 2y+0 ?
forget about my q, u got the derivative correct ! set it equal to 0 and sovle y :)
250 + 1/4(4+π)y = 0 so 250 +y+πy = 0 ?
wait a sec, u have flipped hte sign
\(\large A = 250y - y^2[\frac{4+\pi }{8}]\) \(\large A' = 250 - 2y[\frac{4+\pi }{8}]\)
set it equal to 0 and sovle y
\(\large 250 - 2y[\frac{4+\pi }{8}] = 0 \) \(\large y[\frac{4+\pi }{4}] = 250 \) \(\large y[4+\pi ] = 1000 \) \(\large y = \frac{1000}{4 + \pi} \)
So, the max value occurs at \(\large y = \frac{1000}{4 + \pi} \)
ahh okay so that's it? x= 250 y - (y^2/2) - (pi*y/4) and y = what you just typed?
@ganeshie8 did i get that x value right? :/
u need to sovle x
u have : x + x + y + (π * y / 2 ) = 500
plugin y value in this, and solve x
you should get : \(\large x = \frac{500}{4 + \pi}\)
2x + (1000/4+π) + (π*(1000/4+π / 2) = 500 ?
simplify it in any way u wish ! test for ur algebra skills :P
ahh okay:P thank you!!!
i got 500/4+pi on my paper :) it got messy!! hahahaa
good :) wolfram agrees wid our answer : http://www.wolframalpha.com/input/?i=maximize+xy+%2B++++%5Cfrac%7B%5Cpi+%7D%7B8%7Dy%5E2%2C++x+%2B+x+%2B+y+%2B+%28%5Cpi+*+y+%2F+2+%29+%3D+500%2C+x+%3E+0%2C+y+%3E+0
hehe thanks!! :D
np :)
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