Cassie has 30 grams of cobalt-60 that decays 12% per year. How many years will it take for half of the original amount to decay??? * PLEASE HELP :)*

Question

lena772 · Answer

100-12=88% 

Original amount=30 Half of this=15

1st year   30*88%=26.4
2nd year  26.4*88%=23.232
3rd year 23.232*88%=20.44416
4th year 20.44416*88%=17.9908608
5th year 17.99086087*88%=15.8319575656
6th year  15.8319575656*88%=13.9321226577

A little over 5 years, sometime during the 6th year, half of the original amount will be decayed.

aaronq · Answer

You can find the exact amount of time it will take with those equations:

$ln[A]_t=-kt+ln[A]_o$  and    $t_{1/2}=\dfrac{ln(2)}{k}$

Find the half life of the substance.