Question

differentiate and simplify:
x=tan(x+y)

Answer 1

\[x+y=\tan^{-1} x\]
diff. with respect to x
can you complete it?

Answer 2

\[\frac{ d }{dx }\left( \tan^{-1} x \right)=\frac{ 1 }{ 1+x^2 }\]

Answer 3

do you know ,how to solve it?

Answer 4

\[1+\frac{ dy }{dx }=\frac{ 1 }{1+x^2}\]
find \[\frac{ dy }{ dx }.\]

Answer 5

if you have not leaned inverse trigonometric functions.
you can proceed directly

Answer 6

diff. w.r.t. x
\[1=\sec ^2\left( x+y \right)*\frac{ d }{ dx }\left( x+y \right)\]

Answer 7

that is the first step i know. not
inverse. the answer is cos^2(x+y)-1

Answer 8

i just can't get there

Answer 9

what is \[\frac{ d }{ dx }\left( x+y \right)=?\]

Answer 10

\[=1+\frac{ dy }{dx }\]

Answer 11

thanks, but I need the steps.