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Mathematics 7 Online
OpenStudy (lovelyharmonics):

still trigonometric equations ._.

OpenStudy (lovelyharmonics):

Find all solutions to the equation. 7 sin2x - 14 sin x + 2 = -5

OpenStudy (lovelyharmonics):

@Luigi0210 yay your on! will you help?

OpenStudy (luigi0210):

Start by setting it equal to 0.

OpenStudy (lovelyharmonics):

7 sin2x - 14 sin x -3 = 0

OpenStudy (luigi0210):

Actually, add 5.. remember you do the opposite operation. So \(7sin^2x-14sinx+7=0\), isn't that easier? Now factor~

OpenStudy (lovelyharmonics):

7(sin^2x-2sinx+1) 7(sinx-1)(sinx-1)

OpenStudy (luigi0210):

Nice job :) Don't forget to have that =0 at the end, or else it's just a random expression and not an equation. And right away, you can divide that constant 7 away.

OpenStudy (lovelyharmonics):

aww my ketty dosent show up :c and oh okay and i already did get rid of the seven

OpenStudy (luigi0210):

I'm sorry >.< But yea, that leaves us with \((sinx-1)^2=0\) Can you finish it?

OpenStudy (lovelyharmonics):

isnt that it .-.

OpenStudy (luigi0210):

Nope, solve for x

OpenStudy (lovelyharmonics):

i have no idea how .-.

OpenStudy (luigi0210):

Take the square root of both sides \(sinx-1=\sqrt{0}\) then get sinxx= by itself \(sinx=1\), now where in the unit circle does \(sinx=1\)?

OpenStudy (lovelyharmonics):

at the - sqrt of 0?

OpenStudy (luigi0210):

Where did \(-\sqrt{0}\) come from? \(\color{red}{ლ(゚д゚ლ) }\)

OpenStudy (lovelyharmonics):

well you said sinx−1=√ 0 is the same as sinx=1 so i asumed you just added the 1 to each side and subtracted √ 0

OpenStudy (luigi0210):

Yes, but 0 doesn't add any value so it just disappears. Do you know your unit circle?

OpenStudy (luigi0210):

btw. for trig the coordinate points are \((cosx, sinx)\) And y u be leavin me? \(\large \color{#00FFCC}{ლ(゚д゚ლ) }\)

OpenStudy (lovelyharmonics):

(ノಠ益ಠ)ノ彡┻━┻ my computer shut down, and holy crap what is THAT

OpenStudy (luigi0210):

That would be the unit circle my dear~ You haven't seen it yet?

OpenStudy (lovelyharmonics):

lanope.... you told me about the whole rotating counter clockwise and i already knew that a circle was 360degrees

OpenStudy (luigi0210):

Yes, and \(360^○=2\pi\)

OpenStudy (lovelyharmonics):

i get that they are fractions, but where are the points coming from?

OpenStudy (luigi0210):

30-60-90 and -45-45-90 triangles..

OpenStudy (anonymous):

\(\large \color{#00FFCC}{ლ(゚д゚ლ) } \quad \color{blue}{\text{Looking Nice..:)}}\)

OpenStudy (luigi0210):

Thanks xD And sorry, I'm not good at teaching :( @lovelyharmonics

OpenStudy (lovelyharmonics):

i think you are c: you are one out of only three people i ask for help on here XD

OpenStudy (anonymous):

Trying to be flattery @lovelyharmonics ?? :)

OpenStudy (lovelyharmonics):

say wat? 【・ヘ・?】

OpenStudy (anonymous):

Hehehehe...

OpenStudy (luigi0210):

Thanks.. and you can make that 2 soon because I'm gone later :P Saw what? o.O

OpenStudy (lovelyharmonics):

nonono you not your an abasitor or administer person thus you must stay

OpenStudy (anonymous):

LOL

OpenStudy (luigi0210):

I'm just a regular user like you and most everyone else >.<

OpenStudy (lovelyharmonics):

naw on your profile thats not what is said

OpenStudy (anonymous):

oooooooooooooooooo

OpenStudy (luigi0210):

Wait, why are we talking about this on a question form? >.<

OpenStudy (lovelyharmonics):

wait so how do i figure out where it goes on the circle?

OpenStudy (anonymous):

IDK

OpenStudy (luigi0210):

Look for where sinx=1

OpenStudy (lovelyharmonics):

90degrees?

OpenStudy (luigi0210):

Yup, I'm not exactly sure how to write it in radian terms tho..

OpenStudy (anonymous):

To convert degree into radians just multiply it by pi/180..

OpenStudy (lovelyharmonics):

so its pie/2

OpenStudy (anonymous):

It is one solution only..

OpenStudy (luigi0210):

^I know that, but there is no interval.. I mean like how would you write it with no interval.. is it something like \(\frac{\pi}{2}+2\pi n\)?

OpenStudy (anonymous):

General Solution??

OpenStudy (luigi0210):

YES, general solution.

OpenStudy (anonymous):

Let us go there now..

OpenStudy (anonymous):

\[\sin(x) = \sin(y) \implies \color{red}{x = n \pi + (-1)^n y}\]

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