Question

Let f(x)= 2x+1 and g(x)= x^2-2x. Compute g(x+h)

Answer 1

What is h? Is h f(g(x)) ?

Answer 2

I don't know, it doesn't say

Answer 3

Or is h just a variable so the end result will just be g(x)+h?

Answer 4

I think so. It might?

Answer 5

(Which I doubt)

Answer 6

\[\Large\rm g(\color{orangered}{x})=(\color{orangered}{x})^2-2(\color{orangered}{x})\]So we just need to change the orange part to x+h.
Instead of plugging x into the function, we plug x+h in.\[\Large\rm g(\color{orangered}{x+h})=(\color{orangered}{x+h})^2-2(\color{orangered}{x+h})\]Function notation takes a little getting used to.
From there, expand out the binomial and combine like-terms.

Answer 7

do you distribute the -2 to (x+h)?

Answer 8

Yes.