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Physics 11 Online
OpenStudy (anonymous):

.

OpenStudy (anonymous):

@johnweldon1993

OpenStudy (anonymous):

@ikram002p

mathslover (mathslover):

\(\large \boxed {\sf {\color{blue}{E = \cfrac{Q}{4\pi \epsilon _0 r^2}}}}\) You have been given with : E = Strength of Electric Field = 100 N/C r = distance from the point charge = 5.0 cm Q = magnitude of charge = ? \(\cfrac{1}{4\pi \epsilon_0 } \) = 9 * \(10^9\) \(N m^2 / C^2\) Precaution to take : Notice, that all the other units except "r" are in SI but r is in CGS. So, convert 5 cm to meters.

OpenStudy (anonymous):

thank you @mathslover

mathslover (mathslover):

You're welcome @QueenBee232 :)

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