Question

A projectile is fired from vertically upward from the ground level with an initial velocity if 16 ft/sec, how long does it take for the projectile to hit the ground?

Answer 1

So what is your guess ?

Answer 2

@TheAni-Trix lemme give you a hint!

You have been given
u = initial velocity = 16 ft/sec

and its obivous that its v = final speed = 0 ft/s

and acceleration here would be gravitational acceleration ...i.e. g which is equals to \[9.8 m/s ^{2}\]

so now use the equation
v = u + at

to calculate t and multiply that t with 2 to get your answer..:)

Answer 3

@TheAni-Trix ... try to solve it :)

Answer 4

Why do I multiply t by 2?

Answer 5

@Shizen

Answer 6

TheAnt-Trix, you need to multiply "t" by 2 as the ball will first go up (ascent) and then will come down (descent)

So, time of complete flight = Time of Descent + Time of Ascent

Answer 7

Or Time (T) = 2* t

t = Time of Ascent/Descent

Answer 8

cos the question needs the complete time
of the projectile going up and then returning back

Answer 9

Oh okay, so does that mean that the time to go upward was 1/2?

Answer 10

it was half the time taken by the projectile for returning back :)