In general, matrix multiplication is not commutative. Show by counterexample that this is true. Then give an example of when matrix multiplication is commutative, Explain
@satellite73
pick any matrix make is simple, like a two by two matrix multiply one way and then the other and see that you don't get the same thing
If I don't get the same thing it makes it not commutative or commutative?
\[ \left( \begin{array}{cc} 1 & 2 \\ 3 & 4 \\ \end{array} \right)\times\left( \begin{array}{cc} 3 & 2 \\ 1 & 4 \\ \end{array} \right) \] for example try that one
then try \[\left( \begin{array}{cc} 3 & 2 \\ 1 & 4 \\ \end{array} \right)\left( \begin{array}{cc} 1 & 2 \\ 3 & 4 \\ \end{array} \right)\]
the result will not be the same that shows that \(A\times B\neq B\times A\) which shows they are NOT commutative
= [5 10] [13 22] =[9 14] [13 18] They're different
OHH!
But if they're still the same answer if multiplied both ways means they're commuative?
yeah, that is what it means commutative means for all \(A, B\) \(AB=BA\) not true for matrices
\[ \left( \begin{array}{cc} 1 & 2 \\ 2 & 2 \\ \end{array} \right).\left( \begin{array}{cc} 0 & 1 \\ 1 & 1 \\ \end{array} \right)=\left( \begin{array}{cc} 2 & 3 \\ 2 & 4 \\ \end{array} \right)\\ \left( \begin{array}{cc} 0 & 1 \\ 1 & 1 \\ \end{array} \right).\left( \begin{array}{cc} 1 & 2 \\ 2 & 2 \\ \end{array} \right)=\left( \begin{array}{cc} 2 & 2 \\ 3 & 4 \\ \end{array} \right) \]
Okay I see ^.^ Thank you soo much! You good helpers only come out at night ;P Now I just said need to find a multplication matrix that is commutative
hint use the identity matrix it commutes with everything
Take two diagonal matrices
or what @eliassaab said
Is it okay if I take to same matrix and put them as an example? like this [1 2] [1 2] [1 4] [1 4]
I can't find one @eliassaab
Found one: [1 0] [3 0] [3 0] [0 2] [0 4] = [0 8] [3 0] [1 0] [3 0] [0 4] [0 2] = [0 8]
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