Question

Let f(x) = (x^2-8 x +15)/(x^2+2 x -15) .

Calculate lim (x-> 3) f(x) by first finding a continuous function which is equal to f everywhere except x= 3 .

lim(x-> 3) f(x)=

Answer 1

i guess that translates as "factor and cancel"

Answer 2

(x-5)/(x+5)

Answer 3

i'll take your word for it
then put \(x=3\) and you are done

Answer 4

problem asks for equal to f everywhere except x= 3 .

Answer 5

don't be confused by that
if you factored correctly then
\[\frac{x-5}{x+5}\] is the same as the original function everywhere except \(x=3\) because the original one is not defined at \(x=3\)
you would have a zero in the denominator

Answer 6

oh i see, alright ty