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as x > infinite what is the limit of ( 1/(a/x) )^ bx
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\[\lim_{x\to\infty}\left(\frac{1}{a/x}\right)^{bx}~~?\]
yesss
Depends on \(b\).
it wants the limit usin l'hopitals tho
a should be positive. otherwise you can't compute all powers (i think).
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if b > 0 then you basically have infty^infty = infty
if b = 0 you have 1
if b < 0 let c = -b > 0. You have \(\lim_{x\to\infty}\left(\frac{a}{x}\right)^{cx}\). The base alone approaches 0, and an increasing exponent won't stop it.
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