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Mathematics 25 Online
OpenStudy (anonymous):

Find the minimum and maximum values of x+2y where x and y are lengths in the figure attached inside and 0≤x≤10. **write EXACT answers*** minimum=__________. maximum=___________.

OpenStudy (anonymous):

figure! :D

hero (hero):

Is the figure a "closed" figure?

OpenStudy (anonymous):

umm not sure.. it doesn't specify :/ do you mean like an interval? :/

OpenStudy (anonymous):

Is this calculus?

OpenStudy (anonymous):

yes:)

OpenStudy (anonymous):

|dw:1397195587488:dw|

OpenStudy (anonymous):

|dw:1397195641636:dw|

OpenStudy (anonymous):

\[ y^2 = 5^2 + (10-x)^2 \]

OpenStudy (anonymous):

okay:) using pythagorean theorem right?

OpenStudy (anonymous):

\[ f(x) = x + 2y = x + 2\sqrt{5^2+(10-x^2)} \]

OpenStudy (anonymous):

oh so from here, do we need to find the derivative? :/

OpenStudy (anonymous):

We need to find critical points. Any place where \(f'(x)\) is \(0\) or undefined.

OpenStudy (anonymous):

In this case \(x=0\) and \(x=10\) are critical points as well, simply because they are on the boundary.

OpenStudy (anonymous):

ohh okay:) so here we plug into the original function? f(0)= f(10)= ?

OpenStudy (anonymous):

or is it a different step? haha not sure if i mixed up the concepts :/

OpenStudy (anonymous):

We are only using \(f'(x)\) to find critical points. Once we have all the critical points, we plug them all into \(f(x)\) to find the max and minimum values.

OpenStudy (anonymous):

okay so f(0)=x+2y = 0+2y = 2y? is it like that?

OpenStudy (anonymous):

No, I already told you...

OpenStudy (anonymous):

\[ f(x) = x + 2y(x) = x+2\sqrt{5^2+(10-x)^2} \]

OpenStudy (anonymous):

In short: \[ f(x) = x+2\sqrt{5^2+(10-x)^2} \]

OpenStudy (anonymous):

First find \(f'(x)\). Then find \(f'(x) = 0\) and \(f'(x)\) is undefined.

OpenStudy (anonymous):

ohh okay oops.. my bad!! so \[f(0)=0+2\sqrt{25+(10-0)^2 }\] which equals \[f(0)=0+2\sqrt{125}\] ?

OpenStudy (anonymous):

oh derivative first, then plug in?

OpenStudy (anonymous):

Yes, derivative first. Find all critical points first. Once you have all the critical points, you can plug them into \(f(x)\).

OpenStudy (anonymous):

umm so would the derivative be \[f ' (x) = 0 + \frac{ 2(x-10) }{ \sqrt{x^2-20x+125} }\] ?

OpenStudy (anonymous):

is that what i would be plugging in 0 and 10 into?

OpenStudy (anonymous):

\[ \frac{d}{dx}x = 1 \]

OpenStudy (anonymous):

\[ \frac{d}{dx}2\sqrt{5^2+(10-x)^2} = 2\frac{d}{dx}\sqrt{x^2-20x+125} \]

OpenStudy (anonymous):

Ummm, you can do the rest I think.

OpenStudy (anonymous):

ahh not sure what's happening her :/ is it implicit differentiation?

OpenStudy (anonymous):

*here

OpenStudy (anonymous):

@wio ? :/

OpenStudy (anonymous):

sorry, deriving that part is really confusing me :(

OpenStudy (anonymous):

No, it isn't implicit because I already gave you an explicit function.

OpenStudy (anonymous):

This is the function\[ f(x) = x+2\sqrt{5^2+(10-x)^2} \]You just have to differentiate this function with respect to \(x\).

OpenStudy (anonymous):

ohh okay, thank you!!:)

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