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Calculus1 8 Online
OpenStudy (anonymous):

here is the new question thing

OpenStudy (anonymous):

@SithsAndGiggles

OpenStudy (anonymous):

@SithsAndGiggles

OpenStudy (anonymous):

To recap, you should have (so far) \[\begin{align*} 6.&&\pi\int_1^2\left((\sqrt{y-1})^2-(1-y)^2\right)~dy\\ 7.&&\pi\int_0^1\left((x+1)^2-(x^2+1)^2\right)~dx\\ 8.&&\pi\int_1^2\left((y-2)^2-(\sqrt{y-1}-1)^2\right)~dy \end{align*}\]

OpenStudy (anonymous):

\[\begin{align*}9.&&\pi\int_0^1\left((1-x^2)^2-(1-x)^2\right)~dx\end{align*}\]

OpenStudy (anonymous):

The drawing is in the last post you made, you can refer to it there.

OpenStudy (anonymous):

Thank you so much! I have the drawing from the post.

OpenStudy (anonymous):

For the last one, about \(x=-3\): |dw:1397198350293:dw|

OpenStudy (anonymous):

@SithsAndGiggles are you still here?

OpenStudy (anonymous):

|dw:1397198410459:dw|

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