I actually need help:
v^2=vo^2+2ax can you use that?
may be start from here : \(\large a = -16\)
and use below : Integrating acceleration gives u velocity integrating velocity gives u displacement
laughing out loud at batman.... showing off your physics talent
Guess calculus it is! a = -16 here since it's deceleration, if you integrate acceleration you get v = -16t+ C 0 = -16t+C, where your c will represent initial velocity of the car at t = 0 X <- displacement X = -16t^2/2 +Ct + C2, C2 = constant X = -8t^2+Ct+C2 This is your displacement. 200 - -8t^2+ Ct, 200 because the car moves 200 feet before it stops So we have 2 equations 0 = -16t+C, and 200 = 08t^2+Ct 0 = -16t+ C => C = 16t Now we have 2 unkowns, Can you do the rest?
You can also use energy methods.
\[ mah = \frac 12 mv^2 \]
200 = -8t^2 +(16t)t 200 = t^2 5 = t C = 16t sub in 5 and boom you got your ft/s
using wio's conversation of energy : http://www.wolframalpha.com/input/?i=16*200+%3D+1%2F2*+v%5E2
thank you luigi. thank you for sharing your problems to the world
Conservation of energy, soooo much quicker.
and cool too xD
I doubt he's allowed to use it though :o
but ye your answer is 80 ft/s
*Note to all: Has no physics background whatsoever*
So it is a math question?
Pray to batman, and it will come!
What did the math book tell you about these things?
it is a math question involving anti-derivatives
^
displacement, velocity, acceleration, jerk, skid... what are these mathematically
So are we doing the antideritative of Force with respect to work then?
with respect to distance^
Because that would be nice.
\[ \int_0^{200} 16m \;dx =3200 m \]
Kinetic energy is the antiderivative of momentum with respect to velocity: \[ \int_0^{v_f}mv\;dv = \frac 12 m(v_f)^2 \]
Is that the work done, wio ?
ur first integral...
There, I can do anti-derivatives with energy methods as well.
a=-16
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