The numbers 20,21 and c are a Pythagorean triple . what is the value of c ? A. 22 B.41 C.29 D.25
I will give you a medal :)
For a Pythagorean triple (x,y,z), \(x^2+y^2=z^2\)
\[20^2+21^2=c^2~~~~~c=?\]
Im so confused ....
The formula for a Pythagorean triple is \[a^2+b^2=c^2\] look at the angle below... |dw:1397230756895:dw| where a and b are the legs of the triangle, and c is the hypotenuse. Every such a triangle must fit \[a^2+b^2=c^2\]
In your case, you are told that 20, 21 and c is a Pythagorean triple, so it therefore must fit \[20^2+21^2=c^2\] correct ?
Ok ? But theres numbers for the answers .
yes, can you solve for c, in the equation below? \[20^2+21^2=c^2\]
Ummmmm ... Im bad at math ....
you are given |dw:1397230948214:dw| (I am not going to go off the way from assuming that C is the hypotenuse, because doing that, you won;t get any of the options) ANYWAY.... So, you will set the equation, \[20^2+21^2=c^2~~~~~~~~Correct?\]
I am going to provide the steps to do these equations, and you will love it okay? Prepare....!
1) take square root of each side of the equation ( 20^2+21^2=c^2 ). 2) solve (i.e. calculate) what you get inside the square root on the left side. 3) what is the square rot of the result that you get on the left side?
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