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OpenStudy (anonymous):
I need help with one more question pleaseee!!
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OpenStudy (anonymous):
\[\sqrt{b^4/25} =4\]
OpenStudy (anonymous):
i have to try and solve for b :s
OpenStudy (anonymous):
does it help to know that \(\large \sqrt{\frac{b^4}{25}}=\frac{b^2}{5}\) ?
OpenStudy (anonymous):
yes that helps alot
OpenStudy (anonymous):
don't forget that you are going to get two answers
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OpenStudy (anonymous):
do i have to do a Quadratic Formula?
OpenStudy (anonymous):
oh no much easier than that!
OpenStudy (anonymous):
\[\large \frac{b^2}{5}=4\iff b^2=20\]
OpenStudy (anonymous):
i guess i should ask first is the square root over the whole fraction, or just in the numerator
wasn't quite clear
OpenStudy (anonymous):
\[\large \sqrt{\frac{b^2}{25}}=4\] is what i was reading
is that right?
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OpenStudy (anonymous):
its just the numerator ?
OpenStudy (anonymous):
yes thats right
OpenStudy (anonymous):
wait b^4
OpenStudy (anonymous):
that is what i was asking
is it \[\large \sqrt{\frac{b^2}{25}}=4\] or is it
\[\large \frac{\sqrt{b^4}}{25}=4\]
OpenStudy (anonymous):
the second one
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OpenStudy (anonymous):
ok that is different
if
\[\frac{\sqrt{b^4}}{25}=4\] then
\[\sqrt{b^4}=100\]so
\[b^2=100\]
OpenStudy (anonymous):
you solve that in your head, no quadratic formula
just make sure to write two answers
OpenStudy (anonymous):
ok i got it! thanks c:
OpenStudy (anonymous):
yw
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