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OpenStudy (anonymous):
Calculate ΔH° for the reaction: 4CO(g) + 2NO2(g) → 4CO2(g) + N2(g) Given the following: NO(g) ΔH°f = 91.3 kJ/mol CO2(g) ΔH°f = - 393.5 kJ/mol 2NO(g) + O2(g) → 2NO2(g) ΔH° = -116.2 kJ 2CO(g) + O2(g) → 2CO2(g) ΔHo = - 566.0 kJ
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