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You divide two monomials and still have a fraction. Can this be correct? Explain.
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@whpalmer4
Sure. If the numerator monomial isn't a multiple of the denominator monomial, you'll end up with a fraction.
Thanks :)
You can test this, of course: \[\frac{x+1}{x} = 1 + \frac{1}{x}\]If we had tried it with "real numbers", say \(x=2\), we'd get \[\frac{2+1}{2} = \frac{3}{2} = 1 + \frac{1}{2}\]and that comes as no surprise, right?
If we make \(x\) bigger and bigger, the remainder fraction gets smaller and smaller, but it never quite becomes 0.
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