Write the sum using summation notation, assuming the suggested pattern continues. -1 + 2 + 5 + 8 + ... + 44
\(\Large\color{blue}{ \bf -1 + 2 + 5 + 8 + ... + 44 }\) You can notice that its going +3 every time. it looks like an infinite one here, and the formula that fits would be (I think) \[\Large\color{blue}{ \bf \sum_{n=1}^{∞}~~-1+3(n-1) }\]
if 44 is the last point and no numbers after it, then ... \[\Large\color{blue}{ \bf \sum_{n=1}^{12}~~-1+3(n-1) }\]
is it possible for n to = 0?
I want to ask you a couple question before I answer, okay?
Do you know\[\Large\color{blue}{ \bf a_{n} }~~~and~~~\Large\color{blue}{ \bf a_{n-1}}\] mean ?
because this is what I can pick I'm so lost
In this notation, on the bottom n=1, is saying that you will plug 1 (for n) into -1+3(n-1) to get the first term. and that you will plug 2 (for n) into -1+3(n-1) to get the second term. and that you will plug 3 (for n) into -1+3(n-1) to get the third term.
and with what you've already said, I think it would be the last choice?
Yes! It's the last one! Good job!
thank you so much for the help
No problem!
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