Question

simplify sin Θ/√1-sin Θ

Answer 1

multiply the top and bottom by \(\sqrt{1-\sin\theta}\).

Answer 2

Is it tan^2 Θ ?

Answer 3

Hmmm, actually maybe do \(\sqrt{1+\sin\theta}\)

Answer 4

\[=\frac{ 2\sin \frac{ \theta }{ 2 }\cos \frac{ \theta }{ 2 } }{ \sqrt{\cos ^2 \frac{ \theta }{ 2 }+\sin ^2\frac{ \theta }{ 2 }-2\sin \frac{ \theta }{ 2 }\cos \frac{ \theta }{ 2 }} }\]
\[=\frac{ 2 \sin \frac{ \theta }{ 2 }\cos \frac{ \theta }{ 2} }{ \left( \cos \frac{ \theta }{2 }-\sin \frac{ \theta }{2 } \right) }\]

Answer 5

\[
\frac{\sin \theta \sqrt{1+\sin\theta}}{\sqrt{1-\sin^2\theta}} = \frac{\sin \theta \sqrt{1+\sin\theta}}{|\cos\theta|}
\]

Answer 6

tan Θ

tan2 Θ

1

−1

These are the choices.

Answer 7

there is something wrong in your statement.

Answer 8

You're right. I just checked. The 1-sin Θ is actually 1-sin^2Θ I apoligize, It didn't paste correctly.

Answer 9

is it \[\frac{ \sin \theta }{ \sqrt{1-\sin ^2\theta } }?\]

Answer 10

Yes.

Answer 11

very simple
use \[\sin ^2\theta+\cos ^2\theta=1\]

Answer 12

Wow, that was simple. Thank you so much for all of your time.

Answer 13

yw

Answer 14

\[opp^2+adj^2=hyp^2 \\ \text{ and we know the } adj \text{ and the hyp } \\ \text{ just solve for opp}\]