Question

solve using substitution 3x + 2y = -4
x + 2y = -8

Answer 1

just substitue in 0 to wherever u see y for the x intercept

Answer 2

why 0?

Answer 3

because when y is 0, you will find your x intercept

Answer 4

Err, Lucy that is incorrect.
We're trying to solve 2 linear equations, not one.

Answer 5

okay, how do i solve it @iPwnBunnies

Answer 6

3x+2y=-4
x+2y=-8

x=-2y-8

3(x)+2y=-4 ----->3(-2y-8)+2y=-4 Solve for y then plug in y in the x= equation

Answer 7

does that make sense?

Answer 8

so it would be (2,-5)?

Answer 9

First, solve for one of the variables in one of the equations. I'll do x in the second equation:
\[x + 2y = -8 \]
\[x = -8 - 2y\]
Great! Now plug this x into the other equation:
\[3 (-8 - 2y) + 2y = -4 \]
\[-24 - 6y + 2y = -4\]
\[-4y = 20\]
\[y = - 5\]
We can plug this result into either equation to get y:
\[x + 2(-5) = -8\]
\[x - 10 = -8\]
\[x = 2\]
We can check by plugging x and y into both equations. Hope this helps!

Answer 10

I'm great at late responses, sorry about that! :P