Mathematics
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OpenStudy (anonymous):
LOOK AT ATTACHMENT
medal+fan
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OpenStudy (anonymous):
OpenStudy (anonymous):
complete the square on right hand side.
OpenStudy (anonymous):
i think the graph looks like this |dw:1397261193860:dw|
OpenStudy (anonymous):
@surjithayer
OpenStudy (anonymous):
i want to say the vertex is(5,-16)
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OpenStudy (anonymous):
\[f(x)=x^2-10x+25-25+9=\left( x-5 \right)^2-16\]
you are correct.
OpenStudy (anonymous):
for the y-intecept its going to be (0,9) correct?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
line of symmetry=
OpenStudy (anonymous):
im trying to figure that one out
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OpenStudy (anonymous):
put x-5=0
or x=5
OpenStudy (anonymous):
minimum value=
OpenStudy (anonymous):
okay . i do think the graph is goint to go up
OpenStudy (anonymous):
correct
OpenStudy (anonymous):
now how do i do the part that says "Given the equation above, find f(3)"
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OpenStudy (anonymous):
what about minimum value=?
OpenStudy (anonymous):
ohh well if the graph is pointing up it should be maximum
OpenStudy (anonymous):
minimum value is the y value of vertex
OpenStudy (anonymous):
(0,9)
OpenStudy (anonymous):
for f(3),plug x=3 in the given eq.
minimum value=-16
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OpenStudy (anonymous):
how will the equation look?
OpenStudy (anonymous):
f(3)=x^2-10x+9
OpenStudy (anonymous):
\[f(x)=(x-5)^2-16 \]
\[(x-5)^2\ge 0\]
minimum f(x)=0-16=-16
OpenStudy (anonymous):
\[f(3)=3^2-10*3+9=?\]
OpenStudy (anonymous):
-12 @surjithayer
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OpenStudy (anonymous):
correct.