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Mathematics 15 Online
OpenStudy (anonymous):

LOOK AT ATTACHMENT medal+fan

OpenStudy (anonymous):

OpenStudy (anonymous):

complete the square on right hand side.

OpenStudy (anonymous):

i think the graph looks like this |dw:1397261193860:dw|

OpenStudy (anonymous):

@surjithayer

OpenStudy (anonymous):

i want to say the vertex is(5,-16)

OpenStudy (anonymous):

\[f(x)=x^2-10x+25-25+9=\left( x-5 \right)^2-16\] you are correct.

OpenStudy (anonymous):

for the y-intecept its going to be (0,9) correct?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

line of symmetry=

OpenStudy (anonymous):

im trying to figure that one out

OpenStudy (anonymous):

put x-5=0 or x=5

OpenStudy (anonymous):

minimum value=

OpenStudy (anonymous):

okay . i do think the graph is goint to go up

OpenStudy (anonymous):

correct

OpenStudy (anonymous):

now how do i do the part that says "Given the equation above, find f(3)"

OpenStudy (anonymous):

what about minimum value=?

OpenStudy (anonymous):

ohh well if the graph is pointing up it should be maximum

OpenStudy (anonymous):

minimum value is the y value of vertex

OpenStudy (anonymous):

(0,9)

OpenStudy (anonymous):

for f(3),plug x=3 in the given eq. minimum value=-16

OpenStudy (anonymous):

how will the equation look?

OpenStudy (anonymous):

f(3)=x^2-10x+9

OpenStudy (anonymous):

\[f(x)=(x-5)^2-16 \] \[(x-5)^2\ge 0\] minimum f(x)=0-16=-16

OpenStudy (anonymous):

\[f(3)=3^2-10*3+9=?\]

OpenStudy (anonymous):

-12 @surjithayer

OpenStudy (anonymous):

correct.

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