Calculate the Definite Integral
\[\int\limits_{0}^{2}\frac{ 1 }{ u }- \frac{ 1 }{ u^5 } \]
@surjithayer can you help me out with this one?
do you know how to find an antiderivative?
Yes
what is the antiderivative for this problem?
1/u = ln(x) + C 1/u^5 = -1/4x^4 + C
\[[\ln(2) - \frac{ 1 }{ 4x^4 }] - [\ln(0) - \frac{ 1 }{ 4(0)^4 }\]
thats ment to be 4(2)^4 on the first part
you need to write it as a limit since this is an improper integral
\[\Large\int\limits_{0}^{2}\left(\frac{ 1 }{ u }- \frac{ 1 }{ u^5 }\right)du\] \[\Large\lim_{t\to0^{+}}\int\limits_{t}^{2}\left(\frac{ 1 }{ u }- \frac{ 1 }{ u^5 }\right)du\]
@zarkon Sorry I had to leave, so I just do the same thing but, put t in instead of 0 ?
your integrand is not defined at 0 so you need to take the limit.
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