Question

closed

Answer 1

http://www.algebra.com/algebra/homework/Probability-and-statistics/Probability-and-statistics.faq.question.439480.html

Answer 2

in your case start with 9

Answer 3

From the 9 people there are 9 possible winners and then 8 possible runner-ups, and finally 7 possible third place finishers. We are choosing 3 from 9 and placing them in an order.

The number of possible permutations of M objects chosen from N objects is P(N,M).
Use P(9,3), which is 9 * 8 * 7 = 504.

Answer 4

I got the same answer. I would also add that for the format I used, P(N,M) = N · (N−1) · (N−2) · …

Answer 5

So, does order matter?

Answer 6

10C5 ways, i.e. 10!/(10-5)!5! = 252

Answer 7

576

Answer 8

I'm not sure if that is correct. Give me a few minutes :p

Answer 9

It should be 800, sorry.

Answer 10

Aw it's alright. Thanks for all of the help.

Answer 11

since there can be 8 different numbers for the first digit, 10 for the second or third. So, 8*10*10 = 800.

Answer 12

Np, sorry I jumped the gun on the last one. Good luck!

Answer 13

i need a medal