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Develop the formula for the derivative of \( arcsin x\)
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y = ArcSin(x) x = Sin(y) implicit differentiation...
Pick it up from here
1*dx/dx = Cos(y)*dy/dx
1 = Cos(y)(dy/dx) dy/dx = 1/Cos(y)
y = ArcSin(x), so dy/dx = 1/Cos(ArcSin(x))
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Alright, I think got it, thanks bah~
And now work some trig magic if you have to, I don't remember if this is actually the derivative
@bahrom7893 Can go harder.
One method that works for me is to transform y=arcsin x into the corresponding equation for the sine: sin y=x. All you need to do now is to find the derivative dy/dx using implicit differentiation and remembering the chain rule.
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