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Mathematics 15 Online
OpenStudy (anonymous):

PLEASE HELP. (Stoichiometry Problem)

OpenStudy (anonymous):

|dw:1397270548813:dw|

OpenStudy (rock_mit182):

you mean i the products H2O?

OpenStudy (anonymous):

no. The Product HOH.

OpenStudy (rock_mit182):

is the same because they are talking of water(H2O) lol

OpenStudy (anonymous):

Therefore, I know that step 1 is to balance the equation. Therefore|dw:1397270822671:dw|

OpenStudy (anonymous):

H2O is not the same as HOH, because the coefficients are different.

OpenStudy (rock_mit182):

looks great, but look, you post on how many are needed to produce 11.2 of water ( again H2O)

OpenStudy (rock_mit182):

:)

OpenStudy (rock_mit182):

well, so the next step would be . .

OpenStudy (anonymous):

No idea.

OpenStudy (anonymous):

could you just please solve it, so i can try to deduce it. I really need to understand this for the exam.

OpenStudy (rock_mit182):

\[\frac{ grams }{ mol }\]fin out in the elements of the reactants

OpenStudy (rock_mit182):

you're going to need the periodic table i guess to find the grams of H and O

OpenStudy (anonymous):

for 2 HOH it would be 11.2/20?

OpenStudy (rock_mit182):

\[2H _{2} + O _{2} -> 2H _{2}O\] once you have balanced the equation you are able to answer the a) part because the proportion in mols of the reactants has been found: THERE are Reactants Products 2 moles of H2 2 moles of H2O 1 mol of O2 the coeficient represent the number of moles per compound

OpenStudy (rock_mit182):

in 1 mol of H2O there is 18 grams of H2O

OpenStudy (rock_mit182):

in 2 moles would be 36 grams of H2O

OpenStudy (rock_mit182):

That makes sense to you ?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

what's the next step?

OpenStudy (anonymous):

please help,I understand what you've said I'm just not sure how it connects to a and b

OpenStudy (anonymous):

I mean b

OpenStudy (rock_mit182):

did you already finished a) ?

OpenStudy (anonymous):

yah, it's just the balancing.

OpenStudy (rock_mit182):

yeah but now ou have to find out how many noles there are in 11.2 grams of H2O

OpenStudy (anonymous):

which is what i have no idea how to do

OpenStudy (rock_mit182):

@iPwnBunnies she has a test. could you explain it to her step by step

OpenStudy (ipwnbunnies):

So, you guys did Part A?

OpenStudy (anonymous):

yes

OpenStudy (rock_mit182):

no completly

OpenStudy (anonymous):

oops, no. we have not

OpenStudy (ipwnbunnies):

Omg, Rock seemed to have explained it well.

OpenStudy (anonymous):

you see I have no idea how to find Part A, I know how to find the molecules though.

OpenStudy (ipwnbunnies):

Ok, first find the amount of moles of H2O made from 11.2 grams.

OpenStudy (ipwnbunnies):

\[(11.2 grams)\frac{1 mol}{18 grams} = ? mol\]

OpenStudy (ipwnbunnies):

When you find that, we'll have to use mole ratios to figure out how many moles of each reactant is needed to make ? moles of water. \[H: (? moles H2O)\frac{2 moles H2}{2 moles H2O} = ? moles H2\]

OpenStudy (anonymous):

I know that in one mol of H20 we have eighteen grams. However, we have to moles we have 36

OpenStudy (ipwnbunnies):

\[O2: (? mol H2O)\frac{1 mole O2}{2 mole H2O}\]

OpenStudy (ipwnbunnies):

Yeah, but that's not needed here. We want to convert grams to moles.

OpenStudy (ipwnbunnies):

Sorry, I wrote all that out b/c I have to go. Good luck.

OpenStudy (anonymous):

i guess ill just fail the semester,i seriously dont understand these explanations

OpenStudy (rock_mit182):

dont' say that

OpenStudy (rock_mit182):

I was chemistryphobic

OpenStudy (rock_mit182):

now I realized chemistry is fun and is not so hard

OpenStudy (anonymous):

you know it's ironic though because my teacher gave us a few stoichiometry problems, and I actually solved all of them, and I'm pretty positive they're right.I'll post a question tomorrow and tag you and attach my work so you can double check. But, it's ironic tho because before I left class I specifically asked my teacher to explain this question to me, but she sucks at explaining, so..

OpenStudy (rock_mit182):

;) you'll do it right, cheer yourself up: I know you're smart

OpenStudy (rock_mit182):

certainly the work of a teacher is to know how to explain otherwise. . .

OpenStudy (rock_mit182):

but i understand it happened to me and still

OpenStudy (anonymous):

like I should be good at it, I'm in pre-cal.It's just you mix math and science together and it's just like no.

OpenStudy (rock_mit182):

but this math is too believe me is just arithmetic

OpenStudy (anonymous):

Anyway, it's super late so I have to go,but honestly it would mean the world to me if you could just solve this entire problem for me that way I could see it tomorrow morning, and at least have the worksheet correct which is another grade, and see if I could understand it, and if I have any questions on your work I promise I'll ask cause I really do need to know how to do it, otherwise I wouldnt have spent so much time here,I just dont want you to think Im one of those people just coming for answers. so please solve the entire thing for me on here

OpenStudy (rock_mit182):

SOLVE IT as far you can and I'll help you out, don't be afraid in make mistakes

OpenStudy (rock_mit182):

is the only way to learn ;)

OpenStudy (rock_mit182):

so sleep tight, and I'll see you tomorrow

OpenStudy (anonymous):

well i kinda have to go now. and actually idk my brain is weird because i learn better when i see an example with a full solution, because i can deduce it rather quickly and then apply it to a similar question. when i try to learn from doing i get confused

OpenStudy (rock_mit182):

yeah i know how it feels but is good too try for ourselves annd then compare

OpenStudy (anonymous):

alright, well please be on tomorrow. Ill show you the rest of my problems, and my solutions so you can verify them. (its only 3 more) and ill see if i can do this one which is highly unlikely

OpenStudy (rock_mit182):

or maybe you need to watch some videos of stoichiometry and then aproach to the problem sometimes work for me

OpenStudy (rock_mit182):

think positive and you will see i know sometimes can be tough

OpenStudy (rock_mit182):

but once you get it is a piece of cake

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