As shown, a uniform beam of length d = 1.90m and mass 15.1kg is attached to a wall with a pin at point B. (Figure 3) A cable attached at point A supports the beam. The beam supports a distributed weight w2 = 245N/m . If the support cable can sustain a maximum tension of 1250N , what is the maximum value for w1? Under this maximum weight, what is FBy, the vertical component of the support's reaction force at point B? the figure is attatched in the comments

Question

anonymous · Answer

attachment

theeric · Answer

Hi! I guess $w_1$ is also distributed?

theeric · Answer

Interesting problem.

theeric · Answer

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I think a good first step would be to identify an equation involving the tension... Vague, sorry..

vincent-lyon.fr · Answer

Since the weight is distributed, its value at any point P along the beam must be expressed in N/m.
So w1 and w2 are the values of this distributed weight at each end of the beam.
What the wording of the question does not say (but it is shown in the diagram) is that w(x) is linear wrt x.

I don't think there is any 'fast' way to solve this problem. You will have to establish rotational equilibrium in order to find forces away from the pin. Then you will have to write that the vertical component of the net force is zero.