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Mathematics 7 Online
OpenStudy (anonymous):

A Scientist wants to dilute a 60% acid solution by adding some 20% solution. If she starts with 80ml of 60% solution, how many milliliters of the 20% solution does she need to add to get a resulting 45% acid solution?

Miracrown (miracrown):

did you have any ideas on starting this? :}

Miracrown (miracrown):

did your teacher go over any formulas like M1V1 = M2V2?

OpenStudy (anonymous):

I can't even remember where to start :(

Miracrown (miracrown):

okay, what about did your teacher go over percents by volume?

Miracrown (miracrown):

lets determine how many mL of the desired compound we have in 80 mL of 60% solution? 60% is 60 mL/100mL total

Miracrown (miracrown):

so we can use that as a conversion factor to change the mL total solution to the mL of acid which gives us how many mL of the acid?

OpenStudy (anonymous):

ok that worked :)

Miracrown (miracrown):

great :]

OpenStudy (anonymous):

ok so now where should I start?

Miracrown (miracrown):

if you review what I've wrote above, you'll have a basic idea!

OpenStudy (anonymous):

45ml?

Miracrown (miracrown):

.45*total volume

OpenStudy (anonymous):

but she started off with 80ml total volume?

Miracrown (miracrown):

O.O... hold on.

OpenStudy (anonymous):

x = 20% acid solution 0.60(80) + 0.20x = 0.45(80 + x) solve for x

Miracrown (miracrown):

http://postimg.org/image/w2j6ppyxp/

OpenStudy (anonymous):

Sourwing has it right. Use algebra.

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