A Scientist wants to dilute a 60% acid solution by adding some 20% solution. If she starts with 80ml of 60% solution, how many milliliters of the 20% solution does she need to add to get a resulting 45% acid solution?
did you have any ideas on starting this? :}
did your teacher go over any formulas like M1V1 = M2V2?
I can't even remember where to start :(
okay, what about did your teacher go over percents by volume?
lets determine how many mL of the desired compound we have in 80 mL of 60% solution? 60% is 60 mL/100mL total
so we can use that as a conversion factor to change the mL total solution to the mL of acid which gives us how many mL of the acid?
ok that worked :)
great :]
ok so now where should I start?
if you review what I've wrote above, you'll have a basic idea!
45ml?
.45*total volume
but she started off with 80ml total volume?
O.O... hold on.
x = 20% acid solution 0.60(80) + 0.20x = 0.45(80 + x) solve for x
Sourwing has it right. Use algebra.
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