Write the following in expanded form using logarithmic properties log5 x^3y ---- z^4
can someone please help me
The problem is \[\Large \log_{5} \left(\frac{x^3y}{z^4}\right)\] right?
yes
ok we'll need to use these rules given here http://www.purplemath.com/modules/logrules.htm
do those rules look familiar?
yes
what's the first step? any ideas?
would you do log5 X^3 +log5 Y - log5 Z^4
it just looks wrong for some reason though
you're very close to the final answer
where did i go wrong on it? can you please explain
Here's the full step by step picture (you'll see that you're on the right track)
Use the log rules given on this page http://www.purplemath.com/modules/logrules.htm to get \[\Large \log_{5} \left(\frac{x^3y}{z^4}\right)\] \[\Large \log_{5} \left(x^3y\right)-\log_{5} \left(z^4\right) \ ... \ \text{Use rule 2}\] \[\Large \log_{5} \left(x^3\right)+\log_{5} \left(y\right)-\log_{5} \left(z^4\right) \ ... \ \text{Use rule 1}\] \[\Large 3\log_{5} \left(x\right)+\log_{5} \left(y\right)-4\log_{5} \left(z\right) \ ... \ \text{Use rule 3}\]
So you just needed to use rule 3 to pull those exponents down
ohh okay that makes sense thank you
you're welcome
one more quick question for this question log7p^6q^3r^1/4
would it be like 6log7p + 3log7q + 1/4 log7r
I'm assuming the original expression is \[\Large \log_{7} \left(p^{6}q^{3}r^{1/4}\right)\]
yes
Then \[\Large 6\log_{7} \left(p\right)+3\log_{7} \left(q\right)+\frac{1}{4}\log_{7} \left(r\right)\] is the correct expansion
thank you :)
you're welcome
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