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Can you help solve Integrate 2x/(x-5) using u-substitution
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u=x-5
then x = u+5 and du =dx \[2 \int\limits \frac{u+5}{u} du = 2 \int\limits 1 + 5u^{-1} du\]
I f you write it as follows it would be come easiers \[ \frac{2 x}{x-5}=\frac{10}{x-5}+2 \]
\[2+\frac{ 5 }{ x-5 }+c\]
so would this be the answer?
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You forgot to times 2 as well as to integrate \(5u^{-1}\)
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