Question

A couple of multiple choice questions Medals to the first answer!

Answer 1

Factor completely: 14bx2 − 7x3 − 4b + 2x

(2b + x)(7x2 + 2)

(2b − x)(7x2 − 2)

(2b + x)(7x2 − 2)

Prime

Answer 2

Factor completely: 21x3 + 35x2 + 9x + 15

(3x − 5)(7x2 − 3)

(3x − 5)(7x2 + 3)

(3x + 5)(7x2 − 3)

(3x + 5)(7x2 + 3)

Answer 3

Factor completely: 10xy + 3y + 20ax + 6a

(10x − 3)(y − 2a)

(10x − 3)(y + 2a)

(10x + 3)(y + 2a)

(10x + 3)(y − 2a)

Answer 4

Factor completely: 5ab + 3ay + 5b + 3y

(5b + 3y)(a + 1)

(5b − 3y)(a + 1)

(5b + 3y)(a − 1)

Prime

Answer 5

Factor completely: 4ab − 7ax + 8b − 14x

(4b − 7x)(a + 2)

(4b + 7x)(a + 2)

(4b − 7x)(a − 2)

Prime

Answer 6

Factor completely: 5x(x + 3) + 6(x + 3)

(x + 3)(30x)

(x + 3)(5x + 6)

(x + 3)(11x)

Prime

Answer 7

The first is \[(2b-x)(7x^2 -2)\]

Answer 8

The second is \[ (3x + 5)(7x^2 + 3)\]

Answer 9

@LadyKatsaTheGraceling : Your post would be more helpful if you'd explain how to get started and then guide @Michael_Fails_Math through the factoring process. Please, do NOT do others' work for them and then provide answers without their involvement.

Answer 10

sorry

Answer 11

@LadyKatsaTheGraceling: If you want to help Michael, start with the very first step towards solving the 3rd problem, being careful not to give away any answers. What should Michael do first, and why? next?

Answer 12

@Michael_Fails_Math : Please, Michael, get involved. Show your first efforts towards factoring these expressions. Ask questions. Note that you can check out the possible answers by multiplying the supposed factors together; if the result is the same as the given expression, you have found the factors.

Answer 13

Michael: All of these problems appear to come from the topic, "Factoring by grouping."

Answer 14

Michael, factoring is the decomposition of an object into a product of other objects, or factors, which when multiplied together give the original. So, for problem three you must break it down to get to the original. http://www.mathsisfun.com/algebra/factoring.html this website might help you a bit.

Answer 15

@Michael_Fails_Math : We need to hear from you. Questions? Concerns? Ideas? Please, get involved as best you can.

Answer 16

@LadyKatsaTheGraceling : How would Michael recognize that this is "factoring by grouping?" How would he get started at "factoring by grouping?"

Answer 17

Michael, I suggest you start by finding the similarities between the different groups within the equation. What do you see in 10xy + 3y + 20ax+ 6a ?