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In a group of 1200 people, 468 have brown eyes, 252 have blue eyes, 132 have green eyes, and 348 have black eyes. What is the probability that a person chosen at random from this group has blue eyes?
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see... The sample space here is 1200... lets call n(a) = number of people with blue eyes hence n(a) = 252.. Therefore p(a) = n(a)/sample space which is 252/1200... solve which is 0.2...
subtract the ones you arent looking for and divide the remaining number by the total... from there you can solve for decimal percent or simplify the fraction.
252/1200 = 21/100 = 0.21 = 21% @TaylorDyals
yes exactly what paki did
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