Vertical asymptotes of the rational function for:

f(x)=x+9 divided by x^2-64

thanks, a medal awaits!

Question

Vertical asymptotes of the rational function for:

f(x)=x+9 divided by x^2-64

thanks, a medal awaits!

anonymous · Answer

Youmean this function?
$$f(x)=\frac{ x+9 }{ x^2-64 }$$

anonymous · Answer

yes

anonymous · Answer

First take a look at the points where f(x) is not defined
Can you tell me that point

anonymous · Answer

you must find a point where f(x) is losing continuity

anonymous · Answer

eh...0

anonymous · Answer

wrong

anonymous · Answer

replace x with 0 and see what f(x) is

anonymous · Answer

-8,8

anonymous · Answer

Right

anonymous · Answer

oh I see what you mean because you can factor the denominator right?

anonymous · Answer

then you have a domain to settle

anonymous · Answer

still learning my precalc :)

anonymous · Answer

the numbers must be greater than 0

mathmale · Answer

Please just factor the denominator of $$f(x)=\frac{ x+9 }{ x^2-64 }$$and then let each of the factors of the denominator equal zero.  Write the results as equations:  x = a, x = b, and they will be the equations of your vertical asymptotes.

anonymous · Answer

like (x-8)=0 and (x+8)=0

mathmale · Answer

@Opulentgal :  The best way to re-state your assertion, "the numbers must be greater than 0," is to state:  "The denominator cannot be zero / is undefined  if the den. is zero."

@Opulentgal :  that's great!  Now please solve each of those equations for x.  Remember, you must write the results as equations.