Question

A juggler throws a ball from an initial height of 4 feet with an initial vertical velocity of 30 feet per second, the height of the ball can be modeled by h= -16t^2 +vt+s where t is the time in seconds the ball has been in the air, v is the initial vertical velocity, and s is the initial height. Write an equation that gives you the height of the feet of the ball as a function of time since it left the jugglers hand? Then calculate if the juggler misses the ball how many seconds does it take to hit the ground?

Answer 1

Technically this is a physics question. But i'll answer it anyway.

Answer 2

h=-16t^2+30t+4

Answer 3

and then 0 = 16t^2+30t+4 solve for t

Answer 4

0 = -16t^2+30t+4 by the way i forgot the -

Answer 5

@zimmah: Great start. But please guide ShaneWithrow so that he can find his own solution. We do not do others' work for them or provide them with answers on OpenStudy. Thanks.

Answer 6

i normally do but since the answer was basically given in the question i would not know how to guide him to it.

Answer 7

h= -16t^2 +vt+s is incomplete until the values of two constants are substituted. @ShaneWithrow : Where would you find these two constants, and what are they?

Answer 8

Shane: Please look at the problem statement again: " an initial vertical velocity of 30 feet per second." That's your "v" (meaning "initial velocity). Please substitute "30 feet/sec") for v in the equation h= -16t^2 +vt+s and type your result here. We'll do the same thing in the case of s (s represents the initial height of the ball).