A company builds computers. It costs $6700 to build 10 computers and $12200 to build 20 computers. Which equation models the cost C(x), as a linear function of the number of computers built, x?
Possible answers: A. C(x)=550x-1200 B. C(x)=550x+1200 C. C(x)=1200x-550 D. C(x)=1200x+550
@mathmale
@acxbox22
Daniel, this problem is much like the previous one. You are given two points on a straight line (which may not be immediately obvious); you need to find the equation of this line, doing exactly what we did last time. The two points are (10, $6700) and (20, $12200). Do you see why? Please find the slope of the line passing thru these two points.
Once you've done that, we'll solve your equation for y, which will also be the desired function, C(x).
m=550
y-6700=550(x-10)
y-6700=550x-5500
This looks appropriate, so I'm not going to check the math (yet). Just add $6,700 to both sides of your equation. What do you get?
y=550+1200
That was easy
Daniel, let's check your result. Steal one of the two points. Substitute its x into your formula. Does the resulting y agree with the y-coordinate of your point?
6700=550(10)+1200
6700=5500+1200
Is that what you'd expected? If x=10, y=$6,700?
6700=6700
Yes
Great. Sure looks promising! Now rewrite your equation by substituting the label C(x) for y. What do you get?
C(x)=550x+1200
Got it... thank you
Got it! That's your desired formula! Cool! I need to get off the 'Net now, but very much look forward to working with you again soon! All the best to you, as always.
I also need to leave... Same to you
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